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8 ARITHMETIC.
The principle of this solution can probably be better
understood by resolving these numbers into prime numbers,
and also resolving 1008 into prime numbers ; we then find that
1008 contains all the prime numbers necessary to make 16, 8, 4,
12, 6, 7 and 9.
Prime numbers in
n 1008 are 2 2 2 2
" 16 u 2 2 2 2
8 " 2 2 2
4 « 2 2
" 12 « 2 2 3
6 " 2 3
7
"
7
" 9 "
3 3
3
Solution of Example 2 :
1008
TV 63X7 = 441
| 126 X 5 = 630
i 252 X 1 = 252
T
7
2 84 X 7 = 588
| 168 X 5 = 840
| 144 X 5 = 720
| 126 X 3 = 378
| 112 X 4 = 448
4297 = mi A 2 6 5
Subtraction.
When fractions are to be subtracted, they must first be
reduced to a common denominator, the same as in addition.
Example.
must be reduced to f — f = f
5
Examples.
No. 1.
No. 2.
No. 3.
60
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