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14 DECIMALS.
Solution
:
0.484375 X 16 = 7.75, gives !££, or J^., approximately.
0.484375 X 32 = 15.5, gives ^^, or i.|, approximately.
0.484375 X 64 = 31, gives 1 1 exactly.
If the result does not need to be very exact, probably T%,
which is 6
3
¥ too small, is near enough, or the result, y
iY% may be
called ^, which is -^ too large. |f is -^ too small, therefore
either ]/
2 or \\ is only ¥
x
¥ different from the true value. The
first is
ef too large and the last is ^ too small, and which
fraction, if either, should be preferred, will depend entirely upon
the purpose for which the problem is solved. \\ is the exact
value.
Addition of Decimal Fractions.
In adding decimal fractions, care should be taken to place
the decimal points under each other ; then add as if they were
whole numbers.
Example.
Solution
:
Add 50.5 + 5.05 + 0.505 + 0.0505
50.5
5.05
0.505
0.0505
56.1055
To prevent mistakes and mixing up of the figures during
addition, it is preferable to make all the decimal fractions in
the problem of the same denomination by annexing ciphers.
Thus
:
50.5000
5.0500
0.5050
0.0505
56.1055
Subtraction of Decimal Fractions.
The decimal point in the subtrahend must be placed under
that in the minuend ;
the fractions are both brought to the
same denomination by annexing ciphers, then the subtraction
is performed just as if they were whole numbers, but close
attention must be paid to have the decimal point in the same
place in the difference as it is in the minuend and subtrahend.
Example.
318.05 — 121.6542
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