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346

(1910) Author: Peder Lobben - Tema: Mechanical Engineering
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346 MANILA ROPE TRANSMISSION.
Example.
\Vhat horse-power may be transmitted by a manila rope
\]/
2 inches in diameter, running over nine-foot pulleys at a speed
of 150 revolutions per minute ?
Solution
:
Nine-foot pulleys, running 150 revolutions per minute, give
the rope a velocity of 3.1416 X 9 X 150 = 4241 feet per minute,
and the horse-power transmitted will be
:
h-p = o.oo25 xiy
2 xiy
2 x 4241
H-P = 0.0025 X 2% X 4241
H-P = 23.85 ;
practically, 24 horse-power.
Weight of Manila Rope.
The weight of one foot of manila rope of one-inch diameter is
T
3
o
pound ; therefore, the weight per foot of any size may be
calculated approximately by the formula
:
W=d* X 0.3
d = Diameter of rope in inches.
W= Weight of rope in pounds per foot.
Example.
What is the weight of 360 feet of manila rope of 1^-inch
diameter?
Solution
:
Weight of 360 feet = 0.3X360X1^X1^ = 243 pounds.
TABLE No. 39,
Giving the Weight of Rope in Pounds per Foot, Driving Force in
Pounds, and Corresponding Horse=Power Transmitted at Differ-
ent Velocities.
o,« 4> -j
*fe O O
f*.S
o.S
p=
xt± a
CB
-) 5
Efc,
Horse-power Transmitted at Different Velocities.
«J <u
3 3
lu.S w c
££
° V
8 tt
§ &
(M
1.25 1.56
1.94 2.24
2.81 3.52
5 6.25
7.81 9.77
11.25 14.06
15.31 18.31
20 25
rS6 r"6
tJ-S
2X
2^
3^
5
6^
1
2
0.075
0.12
0.16
0.30
0.47
0.67
0.92
1.20
21
33
47
83
132
186
255
330
0.94
1.45
2.11
3.75
5.86
8.44
11.48
15
2.18
3.39
4.92
8.75
11.7213.73 15.62
16.8719.69 22.50
22.97 26.79 30.62
30 35 |40
1.87
2.90
4.82
7.50
2.50
3.87
5.62
10
3.12 3.75
4.48 5.81
7.03: 8.44
12.50
19.23
28.12
36.61
50
15
23.44
33.75
45.94
60

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