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PULLEYS. 355
The speed of the counter-shaft will be
:
JV= s/ 4S X 256 = 112 revolutions per minute.
As the speed of main lines in factories usually runs at some
multiple of 10, we may, for convenience in getting even-sized
pulleys for connections between counter and main shaft, in
practical work, decide to run the counter-shaft 110 revolutions
per minute.
(When a pair of cone pulleys has an uneven number of
steps, and are cast from the same pattern, the speed of the
counter should be equal to the speed of the machine when the
belt is run on the middle step).
The diameter of the largest step of the cone pulley on the
spindle is 10J^ inches. The corresponding step on the counter
10J£ X 48
will be
Yiq
— = 4.581"; practically, 4)4" diameter.
The largest and smallest step on the counter-shaft will also
be 10^ and 4 l
/
2 inches in diameter.
Any of the intermediate steps on the spindle may be cal-
culated by the formula
:
Bi = (D + d) X N
n + N
Dl = (10^ +4K) X 110 _ 9 065 .
practically) 9 in>
D2 = < 10* + 4 ^> X 110
= n% inches.
110 + no 7
Dz = (ioy
2 + m x no = 5>932 practicall 6 in>
168 + 110
y
Thus, assuming the counter-shaft to run 110 revolutions per
minute, the speed of the spindle, with back gears out, on the five
different steps will be :
110 X 10# __ 265 revoi utj ons per minute.
4^
110 X 9
~6
no x ny
2
110 X 6
9
= 165 revolutions per minute.
= 110 revolutions per minute.
= 73 revolutions per minute.
^ = 47 revolutions per minute.
10J*
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