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19
Exempel (Example) v = 5.
w 0 i 2 3 4 5 6 7 8 9 10 20™ per See.
y qo" &7-°4 46.14 28."i 12."7 0» io.°3 I8.°9 26.°0 3"°9 36.°9 61.»9
du . max. 1 dw il.°9 13 -°6 17*°9 31 "8 oc 26.°0 i i.»9 7-°3 5-°’ 3.°8 o.°8
W 5 4-7 3-9 2-7 1-4 0 1-4 2.8 4.1 5-4 6.7 l8."2 per See.
u 180» i68.°7 I58.»2 I49.»0 i4i.°3 50.°2 54*°5 58.°o 6i.°o 63°4 76."o
e go° ioi.°3 i i i -°8 121 .°o i28.°7 39-°8 35°6 32.°0 29.»! 26.°6 i4.°o
du _ sin u _ w sin y _ w sin y
dv ~ W ~ TFr ~ ws -f- v2—2 w v eos ?/
Maximum haves, ligesom i foregaaende Tilfælde, naar
2 tov
cosy =
w3 -f- Vs’
w
The maximum is reached, as in the foregoing case,
and the maximum value is
Max. du —
_ 180
lU–V2 71
dv.
Ex. v = 5.
du
io 2om per See.
j- max. o° 2.°4 5."5 io.°7 25-°5 oo 3i.°2 i6.°7 n.°7 g.°2 7.°6 3.°i
dv
Q du _ w eos (u—y) _ w eos e _ w (w—v eos y)
dy ~ W ~ W ~ w* + v2—2 w v eos y
Maximum haves, naar sin y = 0 og
Maximumsværdien er W naar y — 0. II" = tv-
w—v’ y
w-\- v
naar y = 180°, W = w + V.
ind.
Ex. v = 5, y — 0, det er Vinden ombord ret for-
The maximum is reached when sin y — 0, and
w-\-v
when y = 180°, W - w + v.
Ex. v = 5, y = 0, i. e. the wind, as felt on board,
being right ahead.
v = 5, y =r 180°, det er Vinden ombord ret agter-
ind.
du
dy
W
w 0123456789 10 2om per See.
^ max. o —Vi — 8/a —*/t —4 6 »/, 8/3 9/4 2 4/s
^5432101234 5
v — 5, y — 180°, that is, the wind, as felt on board,
being right aft.
max. 0 Vs ’h 6/ 111 8/.s */u ">/l5
5 6 7 8 9 IO I I 12 ’3 ■ 4 ■5 25
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